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[audit]#9 improve math precision

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mingda
2020-07-08 18:22:12 +08:00
parent 8dd27f52d3
commit 34b4ba4338
1 changed files with 2 additions and 2 deletions
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contracts/lib/DODOMath.sol
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@@ -85,7 +85,7 @@ library DODOMath {
DecimalMath.ONE.sub(k).mul(4), DecimalMath.ONE.sub(k).mul(4),
DecimalMath.mul(k, Q0).mul(Q0) DecimalMath.mul(k, Q0).mul(Q0)
); // 4(1-k)kQ0^2 ); // 4(1-k)kQ0^2
squareRoot = b.mul(b).add(squareRoot).sqrt(); // sqrt(b*b-4(1-k)kQ0*Q0) squareRoot = b.mul(b).add(squareRoot).sqrt(); // sqrt(b*b+4(1-k)kQ0*Q0)
// final res // final res
uint256 denominator = DecimalMath.ONE.sub(k).mul(2); // 2(1-k) uint256 denominator = DecimalMath.ONE.sub(k).mul(2); // 2(1-k)
@@ -108,7 +108,7 @@ library DODOMath {
uint256 fairAmount uint256 fairAmount
) internal pure returns (uint256 V0) { ) internal pure returns (uint256 V0) {
// V0 = V1+V1*(sqrt-1)/2k // V0 = V1+V1*(sqrt-1)/2k
uint256 sqrt = DecimalMath.divFloor(DecimalMath.mul(k, fairAmount), V1).mul(4); uint256 sqrt = DecimalMath.divFloor(DecimalMath.mul(k, fairAmount).mul(4), V1);
sqrt = sqrt.add(DecimalMath.ONE).mul(DecimalMath.ONE).sqrt(); sqrt = sqrt.add(DecimalMath.ONE).mul(DecimalMath.ONE).sqrt();
uint256 premium = DecimalMath.divFloor(sqrt.sub(DecimalMath.ONE), k.mul(2)); uint256 premium = DecimalMath.divFloor(sqrt.sub(DecimalMath.ONE), k.mul(2));
// V0 is greater than or equal to V1 according to the solution // V0 is greater than or equal to V1 according to the solution